ID · SOC 13-1041 · Most current data

Compliance Officers Salary in Idaho

Median Annual Salary $65,350 -17% below national average (national: $78,420)
$76,660Mean Annual
$31Median Hourly
1,780Employed in State

Idaho ranks 41st of 51 states and D.C. for compliance officers pay, trailing top-paying District of Columbia ($103,010) by $37,660 — a 58% gap.

Salary Range: 10th to 90th Percentile

$65,350
$37,240
10th pct.
$125,410
90th pct.

Full Percentile Breakdown

PercentileAnnual WageHourly Wage
10th percentile (entry-level)$37,240$17.91
25th percentile$47,400$22.79
50th percentile (median)$65,350$31.42
75th percentile$98,650$47.43
90th percentile (top earners)$125,410$60.29
Mean (average)$76,660$36.85

How Idaho Compares

StateMedian Annualvs. Idaho
Idaho (current) $65,350 n/a
District of Columbia $103,010 +58%
New Jersey $93,520 +43%
Massachusetts $92,890 +42%
California $92,350 +41%
Alaska $88,730 +36%
Vermont $88,550 +36%
Delaware $88,450 +35%
Maryland $87,580 +34%

Showing top-paying states with available data. View all states →

Frequently Asked Questions

What is the average Compliance Officers salary in Idaho?

The mean compliance officers salary in Idaho is $76,660 per year. The median (middle) salary is $65,350 per year.

What is the starting salary for a Compliance Officers in Idaho?

Entry-level compliance officerss (10th percentile) in Idaho typically earn around $37,240 per year. Workers at the 25th percentile earn approximately $47,400 per year.

What is the highest Compliance Officers salary in Idaho?

Top earners (90th percentile) in this occupation in Idaho make approximately $125,410 per year. Those in the 75th percentile earn around $98,650 per year.

How does the Idaho Compliance Officers salary compare to the national average?

The median compliance officers salary in Idaho is $65,350, which is -17% below national average of $78,420.

Figures use the most current federal occupational wage survey. All wages are estimates; actual pay varies by experience, education, and employer. About the data.